Calendar Medium Problem


Medium Problems

Problem 1 : jan 1, 1995 was a sunday.what day of the week lies on jan 1,1996?
Solution :            01
                           01
                           96
                           24
                           -1  (since 1996 was leap year)
                        ---------
                    total = 121
                  Then (121)/7 = (17) = 2 odd days
                  Therefore our required day wasMonday.

Problem 2 : On 8th feb,1995 it wednesday. The day of the week on 8th feb,1994 was?
Solution :            04
                           08
                           94
                           23
                        ---------
                  total = 129
                 Then (129)/7 = (18) = 3 odd days
                 Therefore the required day is Tuesday.

Problem 3 : may 6,1993 was thursday.what day of the week was on may 6,1992 ?
Solution :            02
                           06
                           92
                           23
                           -1
                        ----------
                    total = 122
                   Then (122)/7 = (17) = 3 odd days
                   Therefore the required day is Tuesday

Problem 4 : jan 1, 1992 was wednesday. What day of the week was on jan 1,1993 ?
Solution :            01
                           01
                           93
                           23
                       ----------
                   total = 118
                  Then (118)/7 = (16) = 6 odd days
                  Therefore the required day is Friday.

Problem 5: January 1,2004 was a Thursday, what day of the week lies on January, 2005?
solution : the year 2004 being a leap year, it has 2 odd days. so,first day of the 2005 will be 2 days beyond Thursday and so it will be Saturday therefore the required day is Thursday.

Problem 6 : On 8th march, 2005, Wednesday falls what day of the week was it on 8th march,2004?
Solution : the year 2004 being a leap year,it has 2 odd days. so, the day on 8th march,2005 will be two days beyond the day on 8th march,2004.but 8th march,2005 is Wednesday. so,8th march,2004 is Monday.
          Therefore the required day is Monday.

Problem 7: what was the day of the week on 19th September, 1986 ?
Solution :              06
                             19
                             86
                             21
                          ---------
                    total = 132
          Then ((132/7 = 18 and the remainder is 6)
           In the above week table represents the number 6 is friday.
          Therefore the required day is Friday.

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